1932931300 Scott Alan Sanford
Prosthetist
Active
Basic Information
- Full Name
- Scott Alan Sanford
- Gender
- Male
- Enumeration Date
- August 15, 2024
- Last Update
- August 15, 2024
Practice Location
- Address
- 4801 E LINWOOD BLVD
KANSAS CITY, MO 641282226 - Phone
- (816) 861-4700
Mailing Address
- Address
- 4801 E LINWOOD BLVD
KANSAS CITY, MO 641282226 - Phone
- N/A
Specialties & Taxonomies
Specialty | Code | Classification | License | State | Primary |
---|---|---|---|---|---|
Orthotist | 222Z00000X | Orthotist | CPO03213 | N/A | No |
Prosthetist | 224P00000X | Prosthetist | CPO03213 | N/A | Primary |
Frequently Asked Questions
What is Scott Alan Sanford's NPI number?
Scott Alan Sanford's NPI number is 1932931300.
Which doctor has NPI number 1932931300?
The doctor with NPI number 1932931300 is Scott Alan Sanford.
What is Scott Alan Sanford's practice address?
Scott Alan Sanford's practice address is 4801 E LINWOOD BLVD, KANSAS CITY, MO, 641282226.
Which doctor practices at 4801 E LINWOOD BLVD, KANSAS CITY, MO, 641282226?
Scott Alan Sanford practices at 4801 E LINWOOD BLVD, KANSAS CITY, MO, 641282226.
What is Scott Alan Sanford's phone number?
Scott Alan Sanford's phone number is (816) 861-4700.
Who is (816) 861-4700?
(816) 861-4700 is the phone number for Scott Alan Sanford.
What is Scott Alan Sanford's specialty?
Scott Alan Sanford's specialty is Prosthetist.
What type of doctor is Scott Alan Sanford?
Scott Alan Sanford is a Prosthetist.
Is Scott Alan Sanford a Prosthetist?
Yes, Scott Alan Sanford is a Prosthetist.
Is Scott Alan Sanford still practicing?
Yes, Scott Alan Sanford is currently practicing.
Is Scott Alan Sanford accepting new patients?
Scott Alan Sanford may be accepting new patients. Please call their office at (816) 861-4700 to inquire about availability.
Is NPI 1932931300 still active?
Yes, NPI 1932931300 is currently active.
Where does Scott Alan Sanford practice?
Scott Alan Sanford practices in KANSAS CITY, MO.
Is Scott Alan Sanford a male or female doctor?
Scott Alan Sanford is a male doctor.